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Mathematics 24 Online
OpenStudy (anonymous):

Need help with contrapositive. See posted math notation.

OpenStudy (anonymous):

\[For R \subseteq A \times A\] \[[(a,b) \in R \wedge (b,a) \in R] \implies a = b\] I need to find the contrapositive.

OpenStudy (anonymous):

Contrapositive: negate both statements, change the direction of the implication.

OpenStudy (anonymous):

yes, i am aware, but all the notation is confusing to me how to negate.

OpenStudy (anonymous):

so a is not equal to b implies .... lost here

OpenStudy (anonymous):

Can I assume there's no issue with negation of a=b?

OpenStudy (anonymous):

Okay cool.

OpenStudy (zzr0ck3r):

negation of (a^b) is ~a or ~b

OpenStudy (anonymous):

\[(a,b) \notin R \wedge (b,a) \not R\] ?

OpenStudy (zzr0ck3r):

negation of a = b is a != b

OpenStudy (anonymous):

That first part reads thusly: [(a,b)∈R∧(b,a)∈R] if (a,b) is an element of R AND (b,a) is an element of R

OpenStudy (anonymous):

yes. so i am thinking leave the AND as turn to not in R?

OpenStudy (anonymous):

Almost, Sean. But the and sign becomes an or sign. Think about the negation of a statement like I am tall and male. That statement is false if I am short, but it's also false if I'm female. I don't have to be short AND female for it to be false. In general, negation of (a and b) is (not a or not b)

OpenStudy (anonymous):

ok. so something like this:

OpenStudy (anonymous):

\[a \neq b \rightarrow [(a,b) \notin R \vee (b,a) \notin R]\]

OpenStudy (zzr0ck3r):

word

OpenStudy (anonymous):

yussss

OpenStudy (anonymous):

thanks guys. hope i can give you both good answer.

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