A passenger train consists of 2 different locomotives, 6 different passenger cars and 2 different sleeper cars. In how many ways can the cars be arranged if the locomotives must be together and must be at the beginning of the train?

Question

anonymous · Answer

the answer key reads 80640... but i dont know how to get there

ganeshie8 · Answer

2 x 8!

ganeshie8 · Answer

2 locomotives can be arranged at the start of train in ----> 2! ways
8 other cars can be arranged in ----------------------> 8! ways

ganeshie8 · Answer

both combined its 2! x 8!

anonymous · Answer

ya ikr thats exactly ehat i thought but the answer key says its 80640 :(

ganeshie8 · Answer

2! x 8! = 80640

hehehe

ganeshie8 · Answer

http://www.google.co.in/webhp?sourceid=chrome-instant&ie=UTF-8#hl=en&output=search&sclient=psy-ab&q=2!%20x%208!&oq=&gs_l=&pbx=1&fp=d70cb7a1447ca32b&bav=on.2,or.r_gc.r_pw.r_qf.,cf.osb&biw=1822&bih=963

anonymous · Answer

lol.. please help me figure it out

ganeshie8 · Answer

ok.. what u want to figure out... how to compute factorial ?

anonymous · Answer

ooooooHHHHHHH lol thanks soo much!! lol i though u meant 8 x 2 = 16

ganeshie8 · Answer

lol sure u understood ?

anonymous · Answer

yes thank u!!!!! XD

ganeshie8 · Answer

glad to hear that ....  welcome :)))

anonymous · Answer

but how did u know

ganeshie8 · Answer

u want to know how i arrived at 2! x 8!

anonymous · Answer

yes

ganeshie8 · Answer

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