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Mathematics 18 Online
OpenStudy (dariyana):

A triangle has the following measurements. What is a possible length for the third side? AB = 5, BC = 7, CA = ? 2 12 5 13

OpenStudy (dariyana):

@Wired

OpenStudy (dariyana):

i think it B

OpenStudy (lgbasallote):

*greater

OpenStudy (anonymous):

Thanks @lgbasallote , brain fart :) Any two sides when added have to be greater than the third side. Therefore, AB + BC > CA If it was B then AB + AC = CA

OpenStudy (anonymous):

If they were less than or equal to the third side, you wouldn't have a triangle.

OpenStudy (dariyana):

so it would be 13

OpenStudy (eyust707):

|dw:1341624363071:dw|

OpenStudy (eyust707):

i dont think 13 will work

OpenStudy (eyust707):

We could make them all the way flat but they still wouldnt be 13

OpenStudy (dariyana):

when you add the two they equal 12

OpenStudy (eyust707):

Yes so it cant be 12 either

OpenStudy (eyust707):

other wise they would be flat on top of each other

OpenStudy (anonymous):

No. AB + BC > CA 7 + 5 > CA 12 > CA Possible equations: 12 > 2 12 > 5 12 > 12 12 > 13 It's not 12 or 13, because 12 isn't greater than itself, and 12 isn't greater than a large number. Now, since CA = 2 or 5: AB < BC + CA (again, two sides added up are greater than the third) 7 < 5 + 2 7 < 7 7 < 5 + 5 7 < 10 7 can't be less than itself. 7 is less than 10, so you know 5 is the answer.

OpenStudy (eyust707):

12 doesnt work: |dw:1341624504291:dw|

OpenStudy (dariyana):

lol so it 5

OpenStudy (eyust707):

YEP! its 5 Cause 2 is too small |dw:1341624584353:dw|

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