Question

F(x)=A sin Bx
Amplitude?
Period?

Answer 1

A = amplitude

Answer 2

More like |A| since the amplitude is always positive.

Answer 3

2pi/B = period

Answer 4

your forgot phase shift and midline

Answer 5

Idk if were talking about the same thing, so ill upload a picture.

Answer 6

you're talking about #35 and #36 right?

Answer 7

yes sirh.

Answer 8

then yes, we are talking about the same problem...did what was explained/given above make sense?

Answer 9

Not really.

Answer 10

When we look at A*sin(Bx), the amplitude is |A| because this is the value that stretches the graph of sin(Bx) vertically...which dictates how high it peaks and how low it reaches.

Answer 11

Ex: For 3*sin(x), the amplitude is |3| = 3 which tells us that its highest y value is 3 and its lowest y value is -3

Answer 12

does that make sense?

Answer 13

So whats the period?

Answer 14

For A*sin(Bx), the period is \(\Large \frac{2\pi}{B}\)

Answer 15

This basically states that if B were 1, then the period would be 2pi, which is standard for trig functions like sine or cosine

Answer 16

But the period decreases when B increases

Answer 17

Oh, okay. So for number 37 would the amplitude be 2?

Answer 18

You are correct.

Answer 19

And for the period, SR/4 ?

Answer 20

What do you mean SR?

Answer 21

im sorry, i meant pie. lol

Answer 22

What is the value of B?

Answer 23

huh?

Answer 24

In f(x) = -2*sin(x) what is the value of B?

Answer 25

-2?

Answer 26

Remember the general form is f(x) = A*sin(Bx)

Answer 27

Sorry this stuff is new to me.

Answer 28

We can rewrite f(x) = -2*sin(x) as f(x) = -2*sin(1x)

Notice how this matches the form f(x) = A*sin(Bx)

So we can see that A = -2 and B = 1

This is how the amplitude is |A| = |-2| = 2

So B = 1

Answer 29

oh repeated myself a bit in the same message, but I guess that doesn't hurt...lol

Answer 30

Oh, okay. that better.

Answer 31

that's great

Answer 32

but i dont have 1 as a answer choice.

Answer 33

The period in #38 is \(\Large \frac{2\pi}{B} = \frac{2\pi}{1}=2\pi\)

Answer 34

Oh ok. that makes since.

Answer 35

alright great, I'm glad it does

Answer 36

And the last two. Would the amplitude be -1?

Answer 37

The amplitude is always positive. So |-1| = 1 is the amplitude

Answer 38

Oh yeah, i forgot that step. And the period be -pie/2 or just pie?

Answer 39

The period in #40 is \(\Large \frac{2\pi}{B} = \frac{2\pi}{2} = \pi\)

Answer 40

Ok, just checking. Thank you. your such a big help. (:

Answer 41

you're welcome