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ln(e14x) = 7
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What is the base??
base would be 2.718 cause e = 2.718 and ln = 2.718
\[\huge \ln_ex = b\] \[\huge \implies e^b = x\]
so my answer would be 0.1390
Is the question (i) \(ln(e14x) = 7\) or (ii) \(ln(e^{14x}) = 7\)?
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@Callisto Good question.
ln(e14x) = 7
ln(e14x)=7?
The first one or the second one?
the second one
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It's gotta be the 2nd. It's a clean answer :)
yeah
it should be rounded too 0.5
Yep, that's it.
\[lne^{14x} = 7\]\[14x \ln e= 7\]\[14x (1)= 7\]\[x= \frac{7}{14} = 0.5\]
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Note: \(\ln e = 1\)
correct
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