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Mathematics 21 Online
OpenStudy (anonymous):

ln(e14x) = 7

OpenStudy (anonymous):

What is the base??

OpenStudy (anonymous):

base would be 2.718 cause e = 2.718 and ln = 2.718

OpenStudy (anonymous):

\[\huge \ln_ex = b\] \[\huge \implies e^b = x\]

OpenStudy (anonymous):

so my answer would be 0.1390

OpenStudy (callisto):

Is the question (i) \(ln(e14x) = 7\) or (ii) \(ln(e^{14x}) = 7\)?

OpenStudy (anonymous):

@Callisto Good question.

OpenStudy (anonymous):

ln(e14x) = 7

OpenStudy (anonymous):

ln(e14x)=7?

OpenStudy (callisto):

The first one or the second one?

OpenStudy (anonymous):

the second one

OpenStudy (anonymous):

It's gotta be the 2nd. It's a clean answer :)

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

it should be rounded too 0.5

OpenStudy (anonymous):

Yep, that's it.

OpenStudy (callisto):

\[lne^{14x} = 7\]\[14x \ln e= 7\]\[14x (1)= 7\]\[x= \frac{7}{14} = 0.5\]

OpenStudy (callisto):

Note: \(\ln e = 1\)

OpenStudy (anonymous):

correct

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