Question

Solve for x by using base 10 logs.

Answer 1

+11^x+2 = 12^7x

Answer 2

Is this what you mean?:
\[11^x+2=12^{7x}\]

Answer 3

Or\[11^x+2=12^7x\]

Answer 4

or \[11^{x+2}=12^{7x}\]

Answer 5

yea but 11^(x+2) and the first one 12^(7X)

Answer 6

yes

Answer 7

that last one

Answer 8

Okay (equation editor is for your use)
\[11^{x+2}=12^{7x}\]
\[\log_{10}{11^{x+2}}=\log_{10}12^{7x}\]
\[\log_{10}{11^{x+2}}=\log_{10}12^{7x}\]
\[(x+2)\log_{10}{11}=7x\log_{10}12\]
\[(x+2)\log_{10}{11}=7x\log_{10}12\]
\[2\log_{10}{11}=x(7\log_{10}12-\log_{10}{11})\]
\[\frac{2\log_{10}{11}}{(7\log_{10}12-\log_{10}{11})}=x\]
Does that look right?

Answer 9

yep sounds right thnks :)

Answer 10

I don't know why it repeated itself there, but okay.