According to vander waal's equation prove that excluded volume = 4*actual volume i.e b=4v?

Question

According to vander waal's equation prove that excluded volume  = 4*actual volume i.e b=4v?

anonymous · Answer

Excluded volume of 2 molecules is sphere of radius of 2R where R radius of ...Excluded volume for two molecule    
 Excluded volume for one molecule ?
             

        

Constant 'a'measures force of attraction. Greater value 'a', higher intermolecular force of attraction.

anonymous · Answer

okay I got this :

The equation can be cast into the better known form

    \left(p + \frac{n^2 a}{V^2}\right)\left(V-nb\right) = nRT

where

    a = N_A^2a' 

is a measure of the attraction between the particles,

    b = N_A b' 

is the volume excluded by a mole of particles.

anonymous · Answer

i hav nt understood can u xplain it more

anonymous · Answer

Here this should help :D http://en.wikipedia.org/wiki/Van_der_Waals_equation