Question

Please Check:

Answer 1

Mistake in Second One..

Answer 2

I think in the second equation, you should multiply the slope to the value of x as well..

Answer 3

How? for second one
and the last one I dont know if I put the right answer

Answer 4

for the 3rd one
y-4=0(x-5)
y=4
?
I'm not really sure w/ this

Answer 5

\[(y-5) = \frac{-3}{4}(x - 4)\]


\[y - 5 = \frac{-3}{4}x + 3\]

Answer 6

y-5 = (-3/4)x +3
y = -3/4x +8

Answer 7

@rox13kh its said I have to use it s a Point-Slope
@waterineyes ok. so the only thing I messes up is -4, it has to be 3?

Answer 8

Last One will be:

\[y-4 = m(x - 2)\]

As,

\[m = 0\]

\[y = 4\] is the answer..

Answer 9

@waterineyes ok.. so for the last one I just need to put y=4?

Answer 10

@rox13kh you are doing wrong for second problem..

Answer 11

Last one is y = 4. @Trexy

Answer 12

@waterineyes yup, got it thx ^^

Answer 13

@waterineyes ok I got that part now.. thank you..

Answer 14

Welcome dear..

Answer 15

@waterineyes wait.. for the last one I got y=0x-1 because it saying i need to use Slope-Intercept... the one you did, you used Point-Slope?

Answer 16

How will you find intercept c then in the equation:

y = mx + c

m = 0 and c = ??

:Let me check..

Answer 17

Thats the thing I dont know..
Can You ask @lgbasallote, @timo86m or @Calcmathlete or anyone?

Answer 18

I think you will get like this:

\[y = 0x + 4\]

Answer 19

use this formula
y - y1 = m(x - x1)
its easier to deal with

Answer 20

yeah @rox13kh thats wat We used

Answer 21

what is your q?

Answer 22

But it is not the Slope Intercept form @rox13kh

Slope Intercept form is:
y = mx + c..

Answer 23

How will you find intercept c then in the equation:

y = mx + c

m = 0 and c = ??

:Let me check..

plug in what you know and solve for c

Answer 24

y-4=0(x-5)
y=4
but the slope is 0

Answer 25

it is a horizontal line also it is probably undefined.

Answer 26

noo horizontal line has a slope 0
vertical line has an undefined slope

Answer 27

This is the line parallel to x-axis..