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integrate: \[\huge \int \frac{(\ln x)^2}{x}dx\]
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\[\int\frac{(\ln x)^2}{x} dx\] Put \{\ln x=t\] We get \[\frac 1 xdx=dt\] So we have \[\int t^2 dt\] I think you can do now, can't you?
You have to substitute something here..
You know the derivative of lnx is 1/x so use this advantage..
ohhh of course u-sub \[\huge \frac{(\ln x)^3}{3}?\]
Yeah, it's the right answer:D
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Don't forget to add the constant
Oh it is about answer..
oh yeah + C of course haha
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