The number of solutions of the equation 3p + 4q = 70, where p and q are positive integers and p > q, is
hmm...this is linear isnt it?
yup
do you mean the possible values of p and q?
yaa
i would love to say there are infinite solutions because there are no dmain restrictions but i cant be sure
I think either none, infinite or 1.
@igbasallote how did u do that... any explanation
lol didnt i just explain it =))
\[3p + 4q = 70\] \[p = \frac{70 - 4q}{3}\] Now put the values of q like 1, 2, 3 etc and find corresponding q values.. p and q values must be integer.. First one I do for you: Put q = 1, \[p = \frac{70-4}{3} = \frac{66}{3} = 22\] So, one solution is : \[(p, q) = (22, 1)\] Likewise find others.. In total you will have three solutions..
ahh nice work
wow thanxx :)
Welcome dear...
two unknows and 1 equation..solution does make a sense here
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