The number of solutions of the equation 3p + 4q = 70, where p and q are positive integers and p > q, is
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OpenStudy (lgbasallote):
hmm...this is linear isnt it?
OpenStudy (anonymous):
yup
OpenStudy (lgbasallote):
do you mean the possible values of p and q?
OpenStudy (anonymous):
yaa
OpenStudy (lgbasallote):
i would love to say there are infinite solutions because there are no dmain restrictions but i cant be sure
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OpenStudy (zzr0ck3r):
I think either none, infinite or 1.
OpenStudy (anonymous):
@igbasallote how did u do that... any explanation
OpenStudy (lgbasallote):
lol didnt i just explain it =))
OpenStudy (anonymous):
\[3p + 4q = 70\]
\[p = \frac{70 - 4q}{3}\]
Now put the values of q like 1, 2, 3 etc and find corresponding q values..
p and q values must be integer..
First one I do for you:
Put q = 1,
\[p = \frac{70-4}{3} = \frac{66}{3} = 22\]
So, one solution is :
\[(p, q) = (22, 1)\]
Likewise find others..
In total you will have three solutions..
OpenStudy (zzr0ck3r):
ahh nice work
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OpenStudy (anonymous):
wow thanxx :)
OpenStudy (anonymous):
Welcome dear...
OpenStudy (anonymous):
two unknows and 1 equation..solution does make a sense here