a) Write the value of the variable that make the denominator zero b) Keeping the restrictions in mind, solve the equation (x-2/2x)+1 = x+1/x
a) x = 0 b) x= 2
the answer in the book is x=0 x=4
a) is obvious but im having trouble finding b because my answer was zero for b
\[\frac{x-2}{2x} + 1 = \frac{x+1}{x}\]
then you didnt respected the math rules when you copied the equation. is it -2/(2x) or (-2/2)*x
exactly how igb put it
@lgbasallote , ahh... Now we're getting somewhere
x= 4 indeed
idk how you could have taken it any other way...
you just multiply everything by 2x \[x - 2 + 2x = 2(x+1)\] \[3x - 2 = 2x + 2\] \[3x - 2x = 2+2\] \[x = 4\]
do you get that?
tell me if a step is unclear @dylanlamoreaux :)
if you multiply everything by 2x arent you going to get 2x^2 for the right side?
nope \[\frac{x+1}{\cancel x} \times 2\cancel x\]
x just cancels out
\[\frac{x+1}{x} \times 2x = 2(x+1)\]
oh got it
nice!!
cool thanks!
<tips hat>
Join our real-time social learning platform and learn together with your friends!