Question

\[y = \sin (\cot x)\]

okay my question here is just...do you simplify first to \(\cos x\) then derivative? or derivative first then simplify?

Answer 1

i guess, straightway derive ...

Answer 2

so it's product rule right?

Answer 3

ohh lol i thought it was sinx cotx

Answer 4

cot x is the argument..

Answer 5

derive is at sinx and then , derive cot x as well..

Answer 6

so it's \[\cos (\cot x) \times \csc^2 x?\]

Answer 7

\[\csc^2 x \cos (\cot x)\]

Answer 8

\[y=\sin(f(x))\]
\[y'=\sin'((f(x))*f'(x)\]

Answer 9

so...im right right?

Answer 10

\[\cos(cotx)*\cot'(x)\]

Answer 11

...so im right? lol

Answer 12

\[\cos (\cot x) * - cosec ^{2} x \]

Answer 13

negative?

Answer 14

right..

Answer 15

\[-\cos(cotx)*\csc^2x\]

Answer 16

oh wait yeah...derivative of cofunction is negative

Answer 17

thanks guys

Answer 18

w/c..