Question

LGBADERIVATIVE:
\[\huge \frac{\text d}{\text dx} x^{e^{x^2}}\]

Answer 1

rewrite as
\[e^{e^{x^2}\ln(x)}\] and use the chain rule

Answer 2

do you mean \[\ln y = e^{x^2} \ln x?\]

Answer 3

\[\huge x^{e^{x^2}}*lnx* e^{x^2}*2x\]

Answer 4

uhh how?

Answer 5

\[\huge y=a^{f(x)}\]
\[\huge y'=a^{f(x)}*f'(x)*lna\]

Answer 6

oh i see

Answer 7

yeah that makes sense thanks

Answer 8

I made a mistake..

Answer 9

x is not constant
that formula is for constants

Answer 10

\[\huge x^{e^{x^2}}*\left( e^{x^2}*2x*lnx+\frac{e^{x2}}{x}\right)\]

Answer 11

@mukushla you're right, but still we need that formula..