Question

A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 37°
F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by
T(t) = 37 + 46e
– 0.058 t
Find the temperature of the soda 10 minutes after it is placed in the refrigerator. (Round to the
nearest tenth of a degree.)

Answer 1

\[T(0) = 37 + 46e - 0.058\times0\]
\[T(t) = T(0) - 0.058 \times t\]
\[T(10) = T(0) - 0.58\]
\[T(10) = 83 - 0.58 = 82.42 \approx 82.4\]

Answer 2

This question does not involve linear algebra techniques and the equation for T(t) is wrong. It should look more like this:

T(t) = Ts + (To - Ts)*e^(-k*t)

Where k is given as .058, t = 10, To = 83, and Ts = 37.

T(10) = 37 + (83 - 37)*e^(-.058 * 10)
\[T(10) \approx62.8\]
In any event, this question should be closed/ moved to the appropriate forum. Please post Linear Algebra related questions here. Thank you.