Question

Help On Quadratic Equation!!

Answer 1

^^^

Answer 2

\[4\pm \sqrt{6}\]/2 is the answer

Answer 3

how did you get that

Answer 4

first solve 3/y-2 -2
by taking lcm

Answer 5

u will get 7-2y/y-2 on left side of equation

Answer 6

you have
\[ \large \frac{3}{y-2}-2=\frac{1}{y-1}\]
if you multiply the equation by (y-2)(y-1) you get
\[ \large 3(y-1)-2(y-2)(y-1)=y-2 \]
this is the equation!
can you go on by yourself?

Answer 7

\[\frac{3}{y-2} - 2 = \frac{1}{y-1}\]
\[=> \frac{3 - 2(y-2)}{y-2} = \frac1{y-1}\]
\[=>\frac{ 7-2y}{y-2} = \frac1{y-1}\]
\[=>(7-2y)(y-1) = 1(y-2)\]

Now, solve this equation to get a quadratic equation ..

then use the quadratic formula .. i.e
\[\frac{b \pm (b^2 - 4ac)}{2a}\] to get your answer...

Answer 8

okay thanks, Ill try doing it myself now

Answer 9

:)