Question

LGBADERIVATIVE:

\[\huge y = \sqrt{1+xe^{-2x}}\]

Answer 1

\[y^2 = 1+xe^{-2x}\]

Answer 2

\[2yy' = 1 + x(-2e^{-2x} + e{-2x})\]

Answer 3

\[2yy' = 1 -2xe^{-2x} + e^{-2x}\]

Answer 4

\[y' = \frac{1-2xe^{-2x} + e^{-2x}}{2\sqrt{1+xe^{-2x}}}\]

Answer 5

was that right?

Answer 6

no

Answer 7

:O

Answer 8

that 1 again huh...

Answer 9

wait...de javu

Answer 10

i just made the same mistake i did in http://openstudy.com/updates/4ff8d1a7e4b058f8b76342dd

Answer 11

why can i never get that \[\frac{d}{dx} (1) = 0\]
:/

Answer 12

\[y' = \frac{-2xe^{-2x} + e^{-2x}}{2\sqrt{1+xe^{-2x}}}\]
now is it right?

Answer 13

yes

Answer 14

lol i seriously hate this d/dx of 1

Answer 15

I usually get quite a few of my students when I ask something like this...

\[\frac{d}{dx}(\pi^2)\]

Answer 16

some like to write \(2\pi\) :)

Answer 17

when compution a derivative just remember to ignore constants that stand alone

Answer 18

yeah i know...but everytime i do that technique i write 1 haha