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Evaluate the Integral will dras the problem but someone please help me
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\[\int\limits_{1}^{4?} (x ^{2}+\sqrt{x}) dx\]
\[\int_{1}^{4}{x^2}\ dx+\int_{1}^{4}{x^\frac{1}{2}}\ dx\]
oooops!!
its ok
yeah...sum there not a product, sorry. Valpey is correct. use:\[\int\limits_{?}^{?}x^n=\frac{1}{n+1}x^{n+1}\]to integrate each term
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\[\int_{1}^{4}{x^2}\ dx+\int_{1}^{4}{x^\frac{1}{2}}\ dx\] \[\frac{x^3}{3}\ \vert_{1}^{4}+\frac{2}{3}x^\frac{3}{2}\ \vert_{1}^{4}\]
Ohh ok thanks just needed some refreshing.
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