A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?

Question

anonymous · Answer

I had a smiliar problem expect I was asked to find the R. I used R= (Delta V ^2 x time)/mc(T2-T1)

anonymous · Answer

so that is the formula?

anonymous · Answer

My bad, that's not the correct formula for this type of problem. You aren't given the potential difference.

anonymous · Answer

:( actually i can't understand the problem

kropot72 · Answer

$$R _{t}=R _{0}+\alpha t$$
$$R _{t}-R _{0}=\alpha t$$
3 - 1.5 = 0.00375 * t
Now solve for t

anonymous · Answer

why 3?

kropot72 · Answer

Raising the temperature needs to double the resistance. 1.5 ohms * 2 = 3 ohms

anonymous · Answer

t= 3-15 / 0.0037 ??

kropot72 · Answer

$$t=\frac{3-1.5}{0.00375}$$

anonymous · Answer

thanks. so the unit must be degree celsius ?

kropot72 · Answer

Yes. The unit for the answer is degrees Celsius :)

anonymous · Answer

wow thanks a lot. :D

kropot72 · Answer

You're welcome :)