Question

Solve for x in the population: x over x+12 = 1 over x-1

A. x ≈ −6.02 and x ≈ 5.02

B. x ≈ −3.46 and x ≈ 3.46

C. x ≈ −3.14 and x ≈ 4.14

D. x ≈ −2.61 and x ≈ 4.61

Answer 1

\[\frac{x}{x+12}=\frac{1}{x-1}\]?

Answer 2

"cross multiply" get
\[x(x-1)=x+12\]
\[x^2-x=x+12\] then solve the quadratic equation
\[x^2-2x=12\] can you finish it?

Answer 3

umm no...I wanted to be shown how to get the answer.

Answer 4

ok you have a choice
write
\[x^2-2x-12=0\] and use the quadratic formula or keep it at \[x^2-2x=12\] and complete the square
this one does not factor using whole numbers so you cannot do that

Answer 5

since the coefficient \(-2\) it is easiest to complete the square
start with
\[x^2-2x=12\] half of 2 is 1 and 1 squared is also 1 so write
\[(x-1)^2=12+1=13\] take the square root, don't forget the \(\pm\) get
\[x-1=\pm\sqrt{13}\] solve for \(x\) get
\[x=1\pm\sqrt{13}\] to get a decimal use a calculator for \(1+\sqrt{13}\) and \(1-\sqrt{13}\)

Answer 6

hmmm okay im ganna see

Answer 7

No I need the answer...sorry