Can the expression s times the square root of the quantity 64 times s cubed. + 2stthe square root of s. + 8the square root of the quantity 2 times s. be simplified into an expression with fewer terms? Explain and simplify, if possible.

Question

campbell_st · Answer

$$s \sqrt{64s^3} + 2s \sqrt{s} + 8\sqrt{2s}$$

look at the 1st term 

$$s \sqrt{64s^3} = s \times \sqrt{64}\times \sqrt{s^2}\times \sqrt{s}$$

can you simplify this...?

anonymous · Answer

well doesnt the square root of 64 turn into 8

campbell_st · Answer

it does... and there is another part that changes...

campbell_st · Answer

so you are looking at 

$$8s \times \sqrt{s^2}\times \sqrt{s}$$

anonymous · Answer

does the square root of s^7 change

campbell_st · Answer

what does $$\sqrt{s^2}$$

change to..?

anonymous · Answer

wouldnt it be just s^2

campbell_st · Answer

no...

anonymous · Answer

Then i dont know.

campbell_st · Answer

this is what you told me earlier..

$$\sqrt{64} = \sqrt{8^2} = 8$$

use this for 

$$\sqrt{s^2}$$