x(t)= 6(1-cos(t/2)) y(t) = 20t(1-sin(t))((cos(t/2))^2) 0

Question

x(t)= 6(1-cos(t/2)) y(t) = 20t(1-sin(t))((cos(t/2))^2) 0<t<pi. measure the volume inside the these two parametric equations

anonymous · Answer

sorry i have absolutely no idea how to do this

anonymous · Answer

it's ok!

helder_edwin · Answer

you have only two parametric equations!
what course it this for?
book?

anonymous · Answer

it's calculus 2. the question only gave 2 equations, i think we need use the first one to solve t and substituted in to y(t)?

helder_edwin · Answer

still.
you can't find the "volume" of a 2d graph

anonymous · Answer

why i can't ?

helder_edwin · Answer

because it is two-dimensional, it has no volume

anonymous · Answer

can u use this calculate it area? t

anonymous · Answer

then i could use intergral pi*(area)^2 calculate it volume

helder_edwin · Answer

yes i guess
i'm to tired, it's late here.
if you email me the problem i'll try to work on it on me free time
helder_edwin@yahoo.com

anonymous · Answer

no it's by using the integration

anonymous · Answer

one odd thing is that it asks for a volume
why would a curve give a volume?

anonymous · Answer

so we take integrateion from 0 to pi

anonymous · Answer

okay the queastion is strange

anonymous · Answer

look she asked for the section of area that we need it for finding the volume

anonymous · Answer

right

anonymous · Answer

??

anonymous · Answer

so let's think and ask ourself what's the section is

anonymous · Answer

so let's start

anonymous · Answer

|dw:1346984206651:dw|