Find the vertex of the quadratic equation: y = 2x2 + 12x − 4.
First identify a, b, and c terms of the equations. a = 2, b = 12, c = -4
To find x-coordinate of the vertex use the formula x = -b/2a
To find y-coordinate of the vertex use this formula: (c-b^2)/4a
i dont understand im sorry
Do you get the a, b, and c part, just identifying them?
yeah kinda
a is just the number in front of x^2. b the number in front of x and c the number with no x. You cool with that?
yeahh
Okay so, do you know what a vertex is?
yeahh
Okay so you need to find the x and y coordinate of the vertex. and it's given by those two formulas that I gave you. So you can just plug the number we have for a, b, and c into those formulas, yeah?
so x = -(12)/2(2) , yeah?
yess
Cool, so you can find the y-coordinate using the second formula, yes? :) what do you get?
-3 -22 ?
I got -3 for the x coordinate by my answer for y-coordinate is different. Remember c is -4 not positive 4.
so y coordinate = (-4-12^2)/(4(2))
-3 - 50 ?
12^2 = 144
-4 - 144 = -148
4*2 = 8
remember order of operations. Do what's in parenthesis first.
-3 -58 ?
y coordinate is = -148/8
the formula is (c-b^2)/4a first you calculate what's inside of the parenthesis. then you calculate the bottom: 4a. Then you do the top divided by the bottom. (4a).
so what's -148/8?
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