Question

sin^2x(cot^2x+1)=1. How do I prove the identity?

Answer 1

Use the identity
\[\cot^2x+1=\csc^2x\]

Answer 2

Let me try to show you how I would prove this.

\[\cot^s(x)= \cos^2(x)/\sin^2(x)\]
This will lead to the following expression:
\[\sin^2x((\cos^2x/\sin^2x) + 1) = \sin^2x (( \cos^2x + \sin^2x)/\sin^2x)) = \sin^2x((1/\sin^2x)))=1\]
remember that \[\sin^2x+\cos^2x=1 \] the trigonometric pythagoras

Answer 3

thank you very much. that helped a ton!!

Answer 4

You are welcome, pardon the slack typesetting, I am still getting used to this.

Answer 5

no worries.. Im new to this as well so it looks great to me..lol