An object moves along the x axis according to the equation x(t) = (3.00t2 – 2.00t + 3.00) m, where t is in seconds. Determine (a) the average speed between t = 2.00 s and t = 3.00 s, (b) the instantaneous speed at t = 2.00 s and at t = 3.00 s, (c) the average acceleration between t = 2.00 s and t = 3.00 s, and (d) the instantaneous acceleration at t = 2.00 s and t = 3.00 s.

so for

a) I got x(2) = 11
x(3) = 24

b) x'(2) = 10m/s
x'(3) = 16m/s

c) Vxavg = Delta x/ Delta t = (24-11)/(3-2) = 13m/s

d) x''(t) = 6

I'm probably wrong for most of these answers can anyon

Question

An object moves along the x axis according to the equation x(t) = (3.00t2 – 2.00t + 3.00) m, where t is in seconds. Determine (a) the average speed between t = 2.00 s and t = 3.00 s, (b) the instantaneous speed at t = 2.00 s and at t = 3.00 s, (c) the average acceleration between t = 2.00 s and t = 3.00 s, and (d) the instantaneous acceleration at t = 2.00 s and t = 3.00 s.

so for

a) I got x(2) = 11
            x(3) = 24

b) x'(2) = 10m/s
    x'(3) = 16m/s

c) Vxavg = Delta x/ Delta t = (24-11)/(3-2) = 13m/s

d) x''(t) = 6

I'm probably wrong for most of these answers can anyon

australopithecus · Answer

*anyone clarify 

it cut me off

anonymous · Answer

a) I got x(2) = 11
           x(3) = 24
Vxavg = Delta x/ Delta t = (24-11)/(3-2) = 13m/s

anonymous · Answer

b) x'(2) = 10m/s
    x'(3) = 16m/s

anonymous · Answer

c and d) x''(t) = 6  because a is constant for all t
a=6 m/s^2

australopithecus · Answer

I though velocity was displacement/time

australopithecus · Answer

so wouldn't it be 24-11/3-2

anonymous · Answer

yes thats right

australopithecus · Answer

and d) is the second derivative of the function of position so d) is 6

anonymous · Answer

thats right

australopithecus · Answer

alright thanks for confirming for me

anonymous · Answer

welcome dear