Question

Identify the 12th term of a geometric sequence where a1 = 8 and a6 = -8,192.

Answer 1

sorry i know they're all the same

Answer 2

same thing

ar^0 + ar^1

a is 8

-8192=8*r^5

Answer 3

then

using the term in a GP formula

\[a _{n} = a _{1}r^{n -1}\]

\[-8192 = 8r^5\]

solve for r

Answer 4

hmmmm lets see...

Answer 5

then use the formula above with n = 12

Answer 6

can you find r..?

Answer 7

divide both sides by 8

\[r^5 = -\frac{8192}{8} ..... then...... r^5 = -1024\]

Answer 8

mk i got that..... but do u do nething with the ^5?

Answer 9

\[r = \sqrt[5]{-1024}\]

Answer 10

mmmmmkkkkkkkkk................................ im sorry im lost

Answer 11

well r = -4

so you now have the information you need

a = 8 r = -4 and n = 12

substitute it into the formula

\[a _{n} = a _{1} r^{n -1}\]