Question

y=-x^2-6x
I need to find vertex and axis of symmetry.
I got 3,9 for vertex?

Answer 1

no. vertex is (-3, y)

Answer 2

Is this how I do the problem?
-6/2x(-1)?

Answer 3

no...vertex is x=-b/2a...here b=-6 and a=-1. so: x=-(-6)/2(-1)=(6)/(-2)=-3

Answer 4

ok, thank you...

Answer 5

np

Answer 6

here is your parabola's graph. your vertex is at x=-3
http://www.wolframalpha.com/input/?i=y%3D-x%5E2-6x

Answer 7

hold the phone

Answer 8

first coordinate of vertex is \(-3\) second coordinate is what you get when you replace \(x\) by \(-3\)
you get \(-(-3)^2-6\times -3=-9+18=9\)
so your second coordinate was correct, first one was wrong
it is \((-3,9)\)

Answer 9

yeah, I didn't bother with y :)