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derivtives help
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\[h^\prime(x)=2g^\prime(2x)\]
\[F(x)=\frac{f(x)}{h(x)}\] \[F^\prime(x)=\frac{f(x)h^\prime(x)-f^\prime(x)h(x)}{(h(x))^2}\]
ok and what about h'(1)
h'(1)=2g'(2*1)
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Also I have my sign backwards in the quotient rule. Should be...
\[F^\prime(x)=\frac{h(x)f^\prime(x)-h^\prime(x)f(x)}{(h(x))^2}\]
thanks
You bet. Good luck.
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