two groups entering a museum each paid $70. One group included ten adults and four children. The other included five adults and sixteen children. Find the admission price for children and for adults

Question

anonymous · Answer

no i need help please

anonymous · Answer

that is a 16c instead of 6c in the second equation.multiply second equation with 2 then subtract it from the first equation. c will be remaining (the price for children).u can get the value of c.Now put c in any of the equation and find a.

anonymous · Answer

wait arent you salving for c first and then you and you plug that in for the c in 10a+4(6)=70

anonymous · Answer

can you show me how you got 6

shane_b · Answer

Maybe this will make more sense:
$$10a+4c=70$$$$5a+16c=70$$
Solving the second equation for "a" gives you:
$$a=\frac{(70−16c)}{5}$$Now plug this into the other equation and solve for "c":
$$10(\frac{(70−16c)}{5})+4c=70$$You should c = 2.5. Now just plug 2.5 back into one of the original equations and solve for "a":
$$10(a)+4(2.50)=70$$$$a=6$$

shane_b · Answer

I swapped around my a's and c's when I typed it out originally...sorry about that.

shane_b · Answer

Does it make more sense now?