Question

Help please

Answer 1

\[(2^{0}3^{-2})\]

Answer 2

wait wait scractch that

Answer 3

\[(2^{0}3^{-2})^{-2}\]

Answer 4

2^0 is 1

Answer 5

\[2^0=1\] so you can ignore that term. Now multiply the exponents for the second part:\[(3^{-2})^-2=3^{-4}=\frac{1}{3^4}\]

Answer 6

use the laws of exponents

Answer 7

Right, one of the exponent rules says:\[(a^x)^y=a^{xy}\]

Answer 8

so the -4 must be positive, right?

Answer 9

Yea...silly mistake on my part.

Answer 10

\[(3^{-2})^{-2}=3^4\]

Answer 11

thats ok,

Answer 12

Does that (revised) answer make sense @sakigirl ?