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Mathematics 19 Online
OpenStudy (anonymous):

Did i do this right?

OpenStudy (anonymous):

\[x ^{5}y ^{0}z ^{-5}\] and i got 1/\[x ^{5}\]

OpenStudy (anonymous):

no the exponent on the \(x\) term is positive, so it stays in the numerator

OpenStudy (anonymous):

it is the \(z\) that goes in the denominator

OpenStudy (anonymous):

only move the terms with negative exponents

OpenStudy (anonymous):

so the ones with negative u always move it to the denominator?

OpenStudy (anonymous):

if they are in the numerator, move them to the denominator and make the exponents positive yes

OpenStudy (anonymous):

for example \[a^2b^{-3}c^{-2} =\frac{a^2}{b^3c^2}\]

OpenStudy (anonymous):

so if the negative is in the denominator u move it the numerator?

OpenStudy (anonymous):

waitwait nvm haha

OpenStudy (anonymous):

so its x^5 / z^5?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

and yes to your other question if it is negative in the denominator you move it to the numerator and make it positive that is correct

OpenStudy (anonymous):

\[\huge \frac{1}{z^a} = z^{-a}\]

OpenStudy (lgbasallote):

\[z^a = \frac{1}{z^{-a}}\]

OpenStudy (anonymous):

\[\huge \frac{1}{z^a} = z^{-a} \qquad Or \qquad z^a = \frac{1}{z^{-a}}\]

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