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OpenStudy (anonymous):
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OpenStudy (anonymous):
\[x ^{5}y ^{0}z ^{-5}\] and i got 1/\[x ^{5}\]
OpenStudy (anonymous):
no the exponent on the \(x\) term is positive, so it stays in the numerator
OpenStudy (anonymous):
it is the \(z\) that goes in the denominator
OpenStudy (anonymous):
only move the terms with negative exponents
OpenStudy (anonymous):
so the ones with negative u always move it to the denominator?
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OpenStudy (anonymous):
if they are in the numerator, move them to the denominator and make the exponents positive yes
OpenStudy (anonymous):
for example
\[a^2b^{-3}c^{-2}
=\frac{a^2}{b^3c^2}\]
OpenStudy (anonymous):
so if the negative is in the denominator u move it the numerator?
OpenStudy (anonymous):
waitwait nvm haha
OpenStudy (anonymous):
so its x^5 / z^5?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
and yes to your other question
if it is negative in the denominator you move it to the numerator and make it positive
that is correct
OpenStudy (anonymous):
\[\huge \frac{1}{z^a} = z^{-a}\]
OpenStudy (lgbasallote):
\[z^a = \frac{1}{z^{-a}}\]
OpenStudy (anonymous):
\[\huge \frac{1}{z^a} = z^{-a} \qquad Or \qquad z^a = \frac{1}{z^{-a}}\]
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