Question

Part 1: Solve each of the quadratic equations below. Show your work. (3 points)

x2 − 16 = 0 and x2 = −2x + 24

Part 2: Describe what the solution(s) represent to the graph of each. (2 points)

Part 3: How are the graphs alike? How are they different?

Answer 1

1) x2 − 16 = 0
(x+4)(x-4)=0
x=4,-4

Answer 2

Part 1. Solve each quadratic:

x² - 16 = 0 ==> x² = 16 ==> x = ±√16 = ±4 ==> x = -4 and x = 4

x² = -2x + 24 ==> x² + 2x - 24 = 0 ==> (x + 6)(x - 4) = 0 ==> x = -6 and x = 4

The solutions (roots) to these quadratic equations are the x-intercepts, , where the curves cross the x-axis, where y = 0.


Part 2:
The first graph, y = x² - 16, represent an upward-opening parabola with it's vertex at (0,-16) and x-intercepts at (-4,0) and (4,0).

The second graph, y + x² = -2x + 24, also represents an upward-opening parabola with it's vertex at (-1,-25) and x-intercepts at (-6,0) and (4,0).

Answer 3

x2 +2x -24=0
x2 +6x -4x-24=0
(x+6)(x-4)=0
x=4,-6

Answer 4

thankyou double driv do you know part 3 ?

Answer 5

both represents paarabola with axis parallel to y-axis
and each passes through 4,0

Answer 6

graph them and compare them

Answer 7

okay thanks guys