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The value of tan^-1[tan 5pie/6
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tan^-1[tan 5pi/6] ?
yes
this might come in handy \[\huge \tan^{-1} [\tan x] = x\]
that'snot always the case but usually it is
the answer should be -pie/6
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@satellite73
\[\tan^{-1}[\tan x] = x + k\pi \] for as long as k is an integer?
that's simplified form i believe
@yahoo! what are your options
tan^-1 (tan x) = x where x lies in the range of (-pi/2 , pi/2) =>5pi/6 is out of that range we need to re arrange note that tan(5p/6) = tan(pi - pi/6) = -tan(pi/6) now -tan(pi/6) lies in that range so you see why thats the ans..
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