Determine the average rate of change of the function between the given values of the variable. f(t)=2/t; t=a, t=a+h I get (2a-2)/(-a)
the average rate of change is usually defined as :\[\frac{f(x+h)=f(x)}{(x+h)-(x)}\]
*= meant to be a -
I'm using that, not sure where I'm going wrong through
\[\frac{\frac{2}{a+h}-\frac{2}{a}}{a+h-a}\] \[\frac{\frac{2a-2(a+h)}{a}}{h}\] \[\frac{\frac{2a-2a-2h}{a}}{h}\] \[\frac{\frac{-2h}{a}}{h}\] \[\frac{-2\cancel{h}}{a\cancel{h}}=-\frac{2}{a}\] if i did it right
i see a place i messed it at
the answer key says (-2)/a(a+h)
i shoulda combined my denoms :) \[\frac{\frac{2a-2(a+h)}{a(a+h)}}{h}\]
but yeah, it works out to that
i wouldnt know where your going wrong at either,since i cant see your work :)
i got to the first part of your post but am kind of confused at the second
the second part is just working thru the math .... which part gets you lost? other than my mess up with adding the fractions :/
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