Question

How many and of what type are the solutions to x2 + 10x + 25 = 0?

No real solutions

Two identical rational solutions

Two different rational solutions

Two irrational solutions

Answer 1

theres (x+5)(x+5) and there identical rational solutions

Answer 2

so its two identical rational solutions.

Answer 3

i was right jkkkk

Answer 4

wait so you werent right?

Answer 5

@MathDoodler what are you doing?

Answer 6

To solve, use the following formula to find the discriminant
\[ \sqrt{b^2-4ac} \]
Plugin your values from
x2 + 10x + 25 = 0
ax + bx + c = 0


\[ \sqrt{10^2-4(1)(25)} \]
\[ \sqrt{100-100} \]
\[ \sqrt{0} \]
The discriminant = 0

Rule for discriminant
If discriminant = 0 the equation has two equal solutions, a double root
If discriminant > 0 the equation has two unequal real number solution
If discriminant < 0 the equation has two complex number solutions

so your answer is Two identical rational solutions

Answer 7

thank you!

Answer 8

YW

Answer 9

Playing COD and trying to type so that is what was taking me so long lol