A 0.0500-kg lead bullet of volume 5.00 × 10−6 m3 at 20.0 °C hits a block that is made of an ideal thermal insulator and comes to rest at its center. At that time, the temperature of the bullet is 327 °C. Use the following information for lead:
coefficient of linear expansion: α=2.0 × 10−5/C°
specific heat capacity: c = 128 J/(kg ∙ C°)
latent heat of fusion: Lf=23 200 J/kg
melting point: Tmelt =327 °C

1.How much heat was needed to raise the bullet to its final temperature?
2. What is the volume of the bullet when it comes to rest?
3. What additional heat would be needed to melt the b

Question

A 0.0500-kg lead bullet of volume 5.00 × 10−6 m3 at 20.0 °C hits a block that is made of an ideal thermal insulator and comes to rest at its center.  At that time, the temperature of the bullet is 327 °C.  Use the following information for lead:
coefficient of linear expansion: α=2.0 × 10−5/C°
specific heat capacity: c =	128 J/(kg ∙ C°)
latent heat of fusion: Lf=23 200 J/kg
melting point: Tmelt =327 °C

1.How much heat was needed to raise the bullet to its final temperature?
2. What is the volume of the bullet when it comes to rest?
3. What additional heat would be needed to melt the b

fellowroot · Answer

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