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OpenStudy (lgbasallote):
break down the middle term
\[7x^2 + 21x - 5x - 15\]
group
\[(7x^2 + 21x) - (5x + 15)\]
factor out
\[(7x(x+3) - 5(x+3)\]
do you see it now?
OpenStudy (anonymous):
why did you pick 21 and -5? because they add to 16?
OpenStudy (lgbasallote):
yup
OpenStudy (lgbasallote):
and because 21 is a factor of 7...and 5 is a factor of 15
OpenStudy (anonymous):
is that last term supposed to be x+3 or x-3?
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OpenStudy (lgbasallote):
x+3
OpenStudy (lgbasallote):
i factored out -5
OpenStudy (anonymous):
right so -5 * 3 would be -15 dont we want +15?
OpenStudy (lgbasallote):
but the question says -15
OpenStudy (anonymous):
ok so you revert back to the question on the final factoring
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OpenStudy (lgbasallote):
revert back? no
OpenStudy (lgbasallote):
i kept on factoring
OpenStudy (anonymous):
oh sorry i see it now
OpenStudy (anonymous):
it was -15 all along
OpenStudy (lgbasallote):
yes
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OpenStudy (anonymous):
this question is to find the zeros of a polynomial and the books answer s are 5/7,3,-3
OpenStudy (lgbasallote):
3 answers?
OpenStudy (lgbasallote):
that cant be
OpenStudy (lgbasallote):
3 is not a zero
OpenStudy (lgbasallote):
it's just -3
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OpenStudy (lgbasallote):
would you like me to show you?
OpenStudy (anonymous):
maybe im confused, it says find the solution set of 7x^3-5x^2-63x+45 is 5/7,3,-3
OpenStudy (anonymous):
youre right the zero is three
OpenStudy (lgbasallote):
that's a different thing lol
OpenStudy (anonymous):
ya sorry im so burnt out on this stuff
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OpenStudy (anonymous):
zero was the step before
OpenStudy (lgbasallote):
step before what?
OpenStudy (anonymous):
before what we just did
OpenStudy (lgbasallote):
we didnt do any zeroes o.O
OpenStudy (lgbasallote):
you were just asking for factoring..
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OpenStudy (anonymous):
i know i already did that on my own, that doesnt matter now
OpenStudy (lgbasallote):
so what's the question now?
OpenStudy (anonymous):
my question now is how did 7x(x+3)-5(x-2) become 5/7,3,-3
OpenStudy (lgbasallote):
it's not
OpenStudy (lgbasallote):
5/7, 3, -3 are zeroes to a different problem
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OpenStudy (anonymous):
thats the answer for "find the solution set"
OpenStudy (lgbasallote):
find the solution set of 7x^3-5x^2-63x+45 is 5/7,3,-3
OpenStudy (lgbasallote):
see? different problem
OpenStudy (lgbasallote):
we were doing 7x^2+16x-15
OpenStudy (anonymous):
sorry i should have set this up better. its all the same problem. the factoring trouble was after i had broken the big polynomial down through division
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OpenStudy (lgbasallote):
ahh
OpenStudy (lgbasallote):
do you know the zeroes of 7x^2+16x-15 though?
OpenStudy (anonymous):
no
OpenStudy (lgbasallote):
if you do the factoring a while ago
7x(x+3) - 5(x+3)
you get
(x+3)(7x-5)
OpenStudy (lgbasallote):
to get the zero..you equate the factors to zero
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OpenStudy (anonymous):
ohhh got it
OpenStudy (lgbasallote):
when x + 3 = 0
x = -3
OpenStudy (lgbasallote):
when 7x - 5 = 0
7x = 5
x = 5/7
OpenStudy (lgbasallote):
then the other zero which is x = 3
i assume it's the one you divided by
(x - 3)
OpenStudy (anonymous):
yes sir
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OpenStudy (lgbasallote):
so if you equate x - 3 to zero
x = 3
those are your zeroes
-3. 5/7 and 3
OpenStudy (anonymous):
ya perfect thank you
OpenStudy (lgbasallote):
<tips hat>
OpenStudy (anonymous):
hey while i have you, what incentive is there for teachers like you to help on this site?
OpenStudy (anonymous):
is there pay involved? or an internship or something?
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OpenStudy (lgbasallote):
well i have to go but i will tell you that im no teacher...there's no pay..no internship...no something...this is purely voluntary
OpenStudy (lgbasallote):
i for one do it for the love of teaching lol. i like teaching people how to do stuffs
OpenStudy (anonymous):
haha well i really appreciate it.
OpenStudy (lgbasallote):
i believe a lot others do it for the love of teaching as well ^_^ some do it as give and take. ithis site has helped me in my academics as well so i teach too
OpenStudy (lgbasallote):
well im going now. bye
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OpenStudy (anonymous):
thanks again bye!
hero (hero):
@lgbasallote , you made a parenthetical mistake :P