A card is drawn from a deck of well shuffled cards. Determine the probability that the card is either queen or heart.
How many queens are there in 52 cards??
4
Yes.. So probability of selecting a queen will be 4 by 52.. Getting??
yes
And now tell me, how many hearts are there in 52??
4
Really??
Total heart cards are :13
oh yes yes sorry
can you tell me now the probability of choosing a heart??
this i dont understnd, 13 or 12?
What 13 or 12?? There are 13 hearts are there.. Total cards are 52 now find the probability..
13/52
Yes you are right.. Now the required probability is sum of these two probabilities.. Just add 4/52 + 13/52 can you add them??
17/52
Yeah you got it right..
Hold up. There's one thing you forgot. Both of those sums are counting the queen of hearts. That means you also need to subtract 1/52.
no but its the wrong ans
@KingGeorge: i dont get it
There is queen in the heart too... So @KingGeorge is saying right..
Your solution should be 4/52+13/52-1/52. You need to subtract the queen since you've counted it twice.
what is the probability of getting a queen of hearts 1/52 you have to subtract it from the result..
dont understand why we subtract
\[P(A\text{ or }B)=P(A)+P(B)-P(A\text{ and }B)\]
general addition rule
P(A)=4/52
A and B are queen and heart. Right?
yes
Queen and Heart=queen of hearts
What is the problem you are facing??
See, there are 4 queens in 52 cads in which one queen is of heart.. Firstly we find the probability of queen.. Then we find the probability of heats but in there is a queen in hearts too, so probability of getting a heart will be 13/52 But in both the probabilities there is one intersection that is the queen of hearts.. So, total probability will be : \[= \frac{4}{52} + \frac{13}{52} - \frac{1}{52}\]
@waterineyes: Oh thank you, I get it now!
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