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solve for t, t=(10x+1)e^(t)
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Obviously we can solve for x fairly readily: \[t=(10x+1)e^t\] \[te^{-t}=(10x+1)\] \[\frac{te^{-t}-1}{10}=x\] It isn't quite as meaningful to solve for t when the same value of x (-.08 for instance) corresponds to multiple values for t. We would need to split into different functions. Let's find a critical point where dx/dt = 0 and snap the curve there.
I finally got it, its a transcendental equation where you have to approx the e^t term, just figured it out
I'm looking at the Lambert W-function. Learn something new...
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