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Mathematics 22 Online
OpenStudy (raden):

help m please: 200 identical chairs are to be distributed into 4 rooms. If eachroom may have 20, 40, 60, 80 or 100 chairs, how many ways can this be done?

OpenStudy (shane_b):

No my strong area but I did find this answer to this question:

OpenStudy (anonymous):

possible combos are : (100,40,40,20)->4!/2! = 12 (100,60,20,20)->12 (80,60,40,20)->4! = 24 (80,40,40,40)->4 (60,20,60,60)->4 (40,60,40,60)->12 =>12+12+24+4+4+12 = 68

OpenStudy (shane_b):

Even simpler :) GJ

OpenStudy (anonymous):

thank you :)

OpenStudy (raden):

Aryang@ is it filling slot rule??

OpenStudy (anonymous):

i dont know if it is called by some particular name,,sorry..

OpenStudy (raden):

in indonesia called filling slot, how about there??

OpenStudy (anonymous):

i dont know..used basic permutations just,,which i learnt some time ago..

OpenStudy (raden):

nope,, thank's ...

OpenStudy (raden):

shane_B@ can u reexplain ur answer, i still dont get the formula u use?

OpenStudy (shane_b):

I found that answer online. I've never taken classes on permutations but I thought I'd post it anyway in case it helped. I understand @Aryang's answer which I think is more clear.

OpenStudy (raden):

hmmm, i will try get it... thank's for all

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