Mathematics
18 Online
OpenStudy (anonymous):
Please help find the answer :) ....√8/9
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OpenStudy (lgbasallote):
\[\frac{\sqrt 8}{9}\]
what about it?
OpenStudy (anonymous):
I'm supposed to find the value of it and i have the multiple choices for the answer, but I'm confused
OpenStudy (anonymous):
I think the answer is 2sqrt2/3, but I am not sure
OpenStudy (lgbasallote):
first is it \[\frac{\sqrt 8}{9} \; \text{or} \; \sqrt{\frac{8}{9}}\]
OpenStudy (anonymous):
the second one
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OpenStudy (lgbasallote):
ahh
OpenStudy (unklerhaukus):
\[\sqrt{\frac{8}{9}}=\frac{\sqrt {8}}{\sqrt{9}} \]
OpenStudy (lgbasallote):
\[\sqrt{\frac 89} \implies \frac{\sqrt 8}{\sqrt 9}\]
OpenStudy (anonymous):
I'm just really confused.... do I multiply them?
OpenStudy (lgbasallote):
actually you're right
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OpenStudy (unklerhaukus):
\[8=2\times2\times2=2\times2^2=2^3\]
\[9=3\times3=3^2\]
OpenStudy (lgbasallote):
your answer a while ago i mean
OpenStudy (anonymous):
ahaha wait which one?
OpenStudy (unklerhaukus):
\[\frac{\sqrt{8}}{\sqrt{9}}=\frac{\sqrt{2\times2^2}}{\sqrt{3^2}}=\]
OpenStudy (unklerhaukus):
\[=\frac{2\sqrt{2}}{3}.\]
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OpenStudy (anonymous):
2x^2sqrt2/3?
OpenStudy (lgbasallote):
x^2? no
OpenStudy (unklerhaukus):
yep
OpenStudy (anonymous):
oh ok yeah my answer was correct
OpenStudy (anonymous):
just saw my mistake thank you
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OpenStudy (theviper):
\[\Huge{\color{green}{2\sqrt{2}\over{9}}}\]