Question

A train starting from rest is moving with a uniform acceleration of 0.2 m/s^2 for 5 mins , Calculate the speed acquired and the distance traveled in this time...
@Shane_B @angela210793 @lgbasallote @baddinlol

Answer 1

in what time ?? i mean how much time.. ??

Answer 2

a= (v - u)/ t.. this might help..

Answer 3

\[\huge NOW??\]

Answer 4

you can solve it further @Ganpat

Answer 5

k, so t = 5 min..

a= 0.2, u = 0 and v = ??

so, 0.2 = (v-0)/ (5* 30)

v = 150 * 0.2

V = 75 m /s..

Answer 6

okay is that alllllll

Answer 7

@baddinlol is he correct

Answer 8

@Ganpat, doesn't time have to be in seconds?

Answer 9

okay

Answer 10

You used it in minutes..

Answer 11

Your answer

Answer 12

Wait let me solve it.

Answer 13

For speed required

Answer 14

@baddinlol: yes, so i multiplied t by 60..

Answer 15

Use v = u + at

Answer 16

i have done calculation mistake.. sorry

Answer 17

ohh...

Answer 18

k, so t = 5 min..

a= 0.2, u = 0 and v = ??

so, 0.2 = (v-0)/ (5* 60)

v = 300 * 0.2

V = 150 m /s..

this is right

Answer 19

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