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In how many ways can a gymnastics team of 4 be chosen from 9 gymnasts?
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9c4 Combination problem..!!
@Chero did you understand?
Im working it, hold one...
sure :)
not getting the right answer.
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my choices are: 36 126 3,024
Would you share your work here?
is it 3024??
\( \color{Black}{\Rightarrow 9C4 = \Large {9! \over 4! 5! }}\)
nope, you are missing something \[^AC_B=\frac{A!}{B!\times (A-B)!}\]
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Do you understand what factorials are?
9!/(5! x4!) Now solve..:)
braking it down?
Yes. \(9! = 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \)
got it!
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Ans = (6x7x8x9) / (2x3X4)
thank you!
You're welcome :)
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