Question

Is there a solution for this? I'm inclined to think not.

Answer 1

\[\left| z+1 \right|-\left| z-1 \right|=4\]
Where z=a+ib

Answer 2

|z1| − |z2| ≤ |z1 − z2|
let z1=z+1 and z2=z-1

Answer 3

and u r right there is no solution for that

Answer 4

yes there is no solution.


consider the triangle ABC, AB = |z+1|, BC = 2, CA = |z-1|

we know that ABC is a triangle if and only if the difference between two sides is smaller than the third side (a+b > c => c-a < b )

A value of 'z' can exist if and only if ABC is a triangle
AB - CA < BC
=> |z+1| - |z-1| < 2

but this is contradictory to the given statement, hence there is no solution,