Question

Do I make sense?

I shoot a ball with an initial velocity of 8 m/s at an angle of 56 degrees, it takes a projectile shape. I measure its displacement in the x and y directions. This situation was done in real life where there was wind blowing at an unknown velocity.

In the second situation, I take the angle and the initial velocity I gave the ball, and I work out the displacement in x and y when air resistance it ignored.

The different between the displacements is an indication of how much the unknown wind acted on the ball?

Answer 1

assuming, everything else, but the wind, is exactly the same, then yes.

Answer 2

Thank you. I thought so ^^ Suppose I had the velocity of the wind, how to I incorporate it to the velocity of the ball to figure out the change in the displacement? I was able to find the Force of air drag by its equation, any hint on how to go from there?

Answer 3

also, when using F_d = .5 pv^2C_d A <--- do we refer to v as the initial velocity of the ball? or the velocity of the wind? or the velocity of both the ball and the wind?

Answer 4

well, if it is what i think, you just have to draw both vectors and, of course, you need to separate the components, and then just add them. Then you use the motion formula to determin the displacements.

Answer 5

both vectors (the initial velocity of the ball) and the (velocity of the wind) <--- ok, I separate the components, so I add the x components together, and the y together.. then I work out the displacement? @curiousman

Answer 6

I don't need the force of air drag formula?

Answer 7

you do need it. area you familiar with fluid dinamic?

Answer 8

are*

Answer 9

no.

Answer 10

Thanks for your help though. I need to go now. I'll try to think of something simpler.. thanks :)