Question

lim 8x^4-3x^2/ 5x^2+6x as x goes to infinitie.

Answer 1

use l'hopitalsrule

differentiate numerator and denominator

32x^3 - 6x
----------
10 x + 6

= 16x^3 - 3x
----------
5 x + 3

apply rule again

48x ^2 - 3
---------
5

as x approaches infinity this expression approaches infinity

so original expression --> infinity as x --. imfinity

Answer 2

so the anserw would be \[+\infty\] Right?

Answer 3

yes

Answer 4

the original expression = +inf / inf if u sub in x = inf
in this cas ehopital's rule is useful

Answer 5

ok thanks daijones

Answer 6

yw