Question

Can you check if i rationalized the denominator correctly? (its in the comments)

Answer 1

help http://openstudy.com/study#/updates/4ffdd85be4b09082c06f2a1c

Answer 2

\[-3/\sqrt{x}-4\] is \[-3\sqrt{x}+4/x-16\]

Answer 3

This is not correct form:

\[= \frac{-3 \times \sqrt{x}}{\sqrt{x} \times \sqrt{x}} - 4 \implies \frac{-3\sqrt{x}}{x} - 4\]

Answer 4

\[-3 \over \sqrt{x}-4\] is \[3\sqrt{x}+4 \over x-16\]. Better?

Answer 5

\[= \frac{-3 \times (\sqrt{x}+4)}{(\sqrt{x}-4) \times (\sqrt{x} +4)} - 4 \implies \frac{-3\sqrt{x} -12}{x-16}\]

I got this much..

Answer 6

I got -12 first too but i checked it with mathway so now i have no idea which one is correct.

Answer 7

The above that has written by me is correct..
You can trust me..

Answer 8

OK, if you say so.

Answer 9

I am not saying dear..
I have done it very correctly for you..

Answer 10

When you type
\[ -3/\sqrt{x}-4 \]
that means
\[ \frac{-3}{\sqrt{4}}-4 \]
on the other hand (with parentheses)
\[ -3/(\sqrt{x}-4)= \frac{-3}{\sqrt{x}-4} \]

So the answer depends on which is the real question.

Answer 11

I rewrote it in the fourth post.