Calculus optimisation question
Locate Point B to minimise cost of construction.
What's the part you're confused on? Can you show us what you've come up with as a setup so far? To find a local minimum or maximum you'll be finding the critical point(s), which involved finding the derivative of a function. You need to make some functions first! ;-D
Thanks for helping. I am unsure of the functions i need to come up with. Would i use pythagoras?
Can you identify your given stuff first? Constants, rates, etc?
So far i have 4 + (5-x)^2 = r^2 where r is that diagonal
Rate for underwater piping: 240000 \(\large{\frac{$}{mi}}\) Rate for overland piping: 170000 \(\large{\frac{$}{mi}}\)
If 'x' = miles, then the cost of each pipe option to run x miles is?
Use Pythagoras theorem to find out the point B. Like (5-x) and use it in the equation of hypotenuse. Then use your cost parameters to make the cost equation. Differentiate and equate it to zero to solve.
sorry, i am confused... rate of under water piping is 240000/x ?
(240000 \(\large{\frac{$}{\cancel{mi}}}\))(x \(\cancel{mi}\)) = $240000x
miles cancel out, then what @Champs is saying is spot on
|dw:1342039323113:dw| Construct cost equation and differentiate
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