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Mathematics 24 Online
OpenStudy (anonymous):

I need help with arithmetic sequence

OpenStudy (tennistar):

uh ok?

OpenStudy (anonymous):

What is the common difference of a 57–term arithmetic sequence where the first term is –25 and the sum is 17,727? I want to learn how to solve that.

OpenStudy (asnaseer):

do you know the formula for the sum of an arithmetic sequence?

OpenStudy (anonymous):

Yes. But, I don't know what to put where to find the common difference in the equation.

OpenStudy (asnaseer):

can you please show me the formula you are trying to use so that I can then guide you on how to use it?

OpenStudy (anonymous):

\[s _{n} = n(a _{1}+a _{n})\div2\]

OpenStudy (asnaseer):

there is another form of the formula which involves the common difference (d) - do you know that formula?

OpenStudy (anonymous):

\[a _{n}=a _{1}+(n-1)d\]

OpenStudy (asnaseer):

if you put these two together you will get:\[S_n=\frac{n}{2}(2a_1+(n-1)d)\]

OpenStudy (asnaseer):

can you solve it now?

OpenStudy (anonymous):

I don't know what parts go where...

OpenStudy (asnaseer):

\(S_n\) represents the sum to n terms \(n\) represents the number of terms \(a_1\) represents the first term \(d\) represents the common difference

OpenStudy (asnaseer):

it does

OpenStudy (anonymous):

I got it I think.

OpenStudy (asnaseer):

n=57

OpenStudy (anonymous):

\[17,727 = 57\div2(2\times-25+(57-1)d)\]

OpenStudy (asnaseer):

yes - thats right

OpenStudy (anonymous):

\[28.5(8d) = 17,727 ?\]

OpenStudy (asnaseer):

if you are good at algebra then it might be easier to first rearrange the equation

OpenStudy (anonymous):

did i do it right though?

OpenStudy (asnaseer):

no - it doesn't look right to me

OpenStudy (asnaseer):

try starting with:\[\frac{2S_n}{n}-2a_1=(n-1)d\]

OpenStudy (asnaseer):

then plug in the numbers

OpenStudy (asnaseer):

can you see how I got that re-arrangement or do you want me to explain it?

OpenStudy (anonymous):

is d 12?

OpenStudy (asnaseer):

perfect! - well done!

OpenStudy (anonymous):

Thank you :) Do you think you can help me with a few more on my assignment?

OpenStudy (asnaseer):

yw :) please post each question separately on the left and there'll be plenty of people willing to help you in case I am busy.

OpenStudy (anonymous):

Okay :)

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