Question

What is The closed form solution of the integral of e^(x^2)dx??

Answer 1

closed form solution?

Answer 2

solution or integral

Answer 3

oh..so many fancy terms

Answer 4

lol... you are really bouncing around topics, eh? From composition of functions and parabolas yesterday to calculus today? What's up?

Answer 5

a true learner @SmoothMath

Answer 6

lol online math courses!...killin me

Answer 7

\[\huge \int e^{x^2}dx\]
i think i remember this thing as one of those erf function thingies...

Answer 8

Seriously? Yesterday I taught you how to do f(3)/g(4) and today you're learning integrals? That's ridiculous. I don't believe you.

Answer 9

Not even simple integrals...

Answer 10

haha well i dont know what to tell ya..im scholarly...thanks btw igbasallote

Answer 11

the only thing i know about this problem is that if its an integral problem then i can use the maclaurin expansion for e^u...but thats it hahaha

Answer 12

use a quadratic equation to find two real numbers that satisfies the situation. The sum of the two numbers is 7 and their product is 14.

Answer 13

ug this is killing me...there's a reason my username is mathdummy!...

Answer 14

can anyone confirm that this is the correct indefinite integral?....ex^2 dx=1/4 (square root of pi) erfi(x)??

Answer 15

What are the bounds of your integral?

Answer 16

so this is killing you...but you arrived with an answer?

Answer 17

lol ya with some help....its me and 3 other people working on this problem...this is what we collectively got..but im not so sure its right

Answer 18

The function doesn't have an elementary antiderivative. You can do it numerically for whatever finite bounds you want, but if you're talking about integrating to infinity then it's meaningless because the integral doesn't converge.

Answer 19

but what about the expansion of the integral at x=infinity? cant that be done?

Answer 20

No, that function blows up. If you were talking about
\[\int e^{-x^2} dx\]

then it'd be different, but if the argument of the exponent is +x^2, as x gets larger that thing skyrockets to infinity.

Answer 21

ok....well thanks for your help!! i'll report back to my team haha

Answer 22

SmoothMath at once lost for words i see?:)

Answer 23

What you said earlier is (almost) true, by the way.
\[ \int e^{x^2} dx = \frac{1}{2} \sqrt{\pi}\space \text{erfi(x)} \]
If that's what you consider closed form, then that's fine....

Answer 24

sweet!! im surprised we got so close!!! thanks so much for your help!!

Answer 25

I still think you're trolling me.

Answer 26

No problem. But just to clarify, that's not any extra insight into the solution, because the whole definition of erfi(x) is
\[\text{erfi(x)} = \frac{2}{\sqrt{\pi}} \int_0^x e^{t^2}dt\]

Answer 27

It's like saying
\[x^4 - x^3 + 3x^2 - x =0 \]
is solved by
\[x = \Omega\]
where I define
\[\Omega\]
to be the solution to the equation
\[x^4 -x^3 + 3x^3 -x = 0\]

Answer 28

well tomorrow im going back to my functions smoothmath haha...this calculus stuff is way to intense for me....and ya jemurray we were just trying to get a base for the indefinte integral....thanks again it REALLY did help

Answer 29

Who switches each day between learning basic algebra and calculus?

Answer 30

this girl:) ... i like a challenge but even i have to admit defeat at this point..iv been lost all night