Question

Did i simplify this correctly?

Answer 1

\[\sqrt 5n^2 \over \sqrt9m^2\] simplifies down to 5n/9m correct?

Answer 2

is n^2 and m^2 in the square root too?

Answer 3

Yes. The whole thing is squared

Answer 4

\[\sqrt{5n^2\over9m^2}\]

Answer 5

the square root and the squared WOULD negate each other. I think you are correct

Answer 6

\[\frac ab \ne \frac{a^2}{b^2}\]

Answer 7

oh wait. i retract that. listen to terminator

Answer 8

Because i am getting both that and \[n \sqrt{5} \over 3\sqrt{m}\] and i want to know which one is correct. I have faith in you, human/computer combo!

Answer 9

\[\sqrt{\frac{5n^2}{9m^2}} \implies \frac{\sqrt {5n^2}}{\sqrt{9m^2}}\]
square root of n^2 is n and square rootof m^2 is m
\[\frac{\sqrt{5n^2}}{\sqrt{9m^2}} \implies\frac{n\sqrt 5}{m\sqrt 9}\]
now square root of 9 is just 3 so
\[\frac{n\sqrt 5}{m\sqrt 9} \implies \frac{n \sqrt 5}{3m}\]

Answer 10

the latex looks good

Answer 11

I meant to type 3m and got messed up. But so it wouldn't negate because \[\sqrt{5n^2} = \sqrt{5*n*n} \] correct? Or why does it not cancel out?

Answer 12

hmm?

Answer 13

negate what?

Answer 14

Cancel out the square root with the ^2.

Answer 15

only for n

Answer 16

\[\sqrt{n^2} \implies n\]

Answer 17

But if it has a coefficient it does not?

Answer 18

\[\sqrt{5n^2} \implies n\sqrt 5\\ \sqrt{(5n)^2} \implies 5n\]

Answer 19

only the one with square gets taken out